Write an equation of the line that passes through the point (6,2) with slope 3

y = 3x -16

Step-by-step explanation:

We can use the slope intercept form of the equation

y = mx+b where m is the slope and b is the y intercept

We know the slope

y = 3x+b

Substitute the point into the equation to find b

2 = 3(6) +b

2 =18+b

Subtract 18 from each side

2-18 = b

-16 =b

Substitute this back into the equation

y = 3x -16

∠cbe and ∠deb are same-side interior angles.

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