A rocket is launched from the top of a 100-foot cliff with an initial velocity of 34 feet per second. The height of the rocket t seconds after launch is given by the equation h=−16t2+34t+100. How high will the rocket be after 1 second?

118 feet

Step-by-step explanation:

h= -16t² + 34t +100

In order to find the height of the rocket after 1 second, we substitute t=1 in the above equation

h= -16(1)² + 34(1) +100

h=-16 + 34 +100

h=118 feet

Thus, the rocket will be 118 feet high after 1 second

21

jk it's 20

step-by-step explanation:

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870