The length of a rectangle is 5 inches more than its width, x.The area of a rectangle can be represented by the equation x^2=+5X=300.What are the meausres of the width and the length?

Width = 15 inches

length = 20 inches

Step-by-step explanation:

Let

width  = x

According to the question the length of the rectangle is 5 inches more than it width. Therefore,

length = x + 5

Area of a rectangle = LW

where

L = length

W = width

Area of the rectangle

x² + 5x = 300

x² + 5x - 300 = 0

Find the number you can multiply to give you -300 and add to give you 5. The numbers are -15 and 20

x² - 15x + 20x -300 = 0

x(x - 15) + 20(x - 15)

(x - 15)(x + 20) = 0

x = 15 or - 20

we can't use - 20 since it is negative.

Recall

width = x = 15

length = x + 5 = 15 + 5 = 20

Width = 15 inches

length = 20 inches

b

step-by-step explanation:

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180