Today, gasoline prices are $3.44 per gallon. One year ago, gasoline prices were $3.75 per gallon.
Part A
Determine the percent change in the gasoline price from a year ago to today.
Part B
Show how you calculated this change and interpret its meaning in the context of this problem.

PLEASE EXPLAIN!!!

Today, gasoline prices are $3.44 per gallon.

One year ago, gasoline prices were $3.75 per gallon.

Part A

=> The change is: 3.44 - 3.75 = -0.31

=> The percent change is: -0.31/3.75 = -0.083 = -8.3% of last year's price.

Part B

You calculate the change by subtract the current year's price to the last year's price. If the change is negative, it means the price is down. If the change is positive, it means the price is up.

Next, you divide last year's price by the change to get the percent change.

This negative percent change (-P) can be seen as the fact that last year you bought an amount of gallon which cost 100$, this year, you buy the same amount, you have a discount which is equal to P dollar.

Hope this helps!

:)

x -

median = 1.25

range = 12-14.5

interquartile = q12-q14.5

y -

median = 1

range = 15-17

interquartile = q15-q17

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.