Solve for the value of each letter.
1. 6x + 10 = 28
2. -2m - 4 = 8
3. x + x + 2x = 48
4. 3y + 4 + 3y - 6 = 34
5. 9( w - 6 ) = 36
6. -5 ( t + 3 ) = -30
7. 5z + 2 = 3z - 10
8. 11 + 3x + x = 2x - 11
9. -5 ( n -1 ) = 7 ( n + 3 )
10.-3 (c - 4 ) -2c - 8 = 9 ( c + 2 ) + 1

Step-by-step explanation:

1] 6x + 10 = 28  {subtract 10 from both sides}

6x + 10 -10 = 28 - 10

6x = 18  {Divide both sides by 6}

6x/6 = 18/6

x = 3

2]  -2m - 4 = 8 {Add 4 to both side}

 -2m - 4 + 4 = 8 + 4

-2m = 12  {Divide both sides by -2}

-2m/-2 = 12/-2

m = -6

3] x + x + 2x = 48  {add the like terms}

  4x = 48  {divide both sides by 4}

4x/4 = 48/4

x = 12

4] 3y +4 +3y  - 6 = 34 {add the like terms}

   6y - 2 = 34  {Add 2 to both side}

6y - 2 + 2 = 34 +2

6y = 36 {divide both sides by 6}

6y/6 = 36/6

y = 6

5]9(w - 6) = 36 {divide both sides by 9}

[9(w - 6)]/9 = 36/9

w - 6 = 4  {Add 6 to both sides}

w - 6 + 6 = 4 + 6

w = 10

answer:

(-8,7)

explanation:

we know that  

f

(

−

3

)

=

7

therefore, if we wish to get the output as 7, in the function, we need to have our input to be -3.

looking at the function  

f

(

x

+

5

)

, what should the value of x be, such that the input in the function becomes 7?

we simply equate the terms,

x

+

5

=

−

3

x

=

−

8

thus, the point on the new function would be  

(

−

8

,

7

)

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.