A normal distribution has a mean of 104 and a standard deviation of 1.9.

What is the z-score of 108?

Work Shown:

x = 108 is the raw score we want to transform

mu = 104 is the mean

sigma = 1.9 is the standard deviation

z = (x-mu)/sigma

z = (108-104)/1.9

z = 4/1.9

z = 2.10526315789473 which is approximate

z = 2.11 rounding to two decimal places

I'm rounding to two decimal places because many z tables will work with this level of precision.

  b.   the average rate of change of f(x) is less than the average rate of change of g(x).

step-by-step explanation:

since the length of the interval is the same in each case, we only need to compare the change in y-value to see which is greater.

so the change in y-value for function f is (6 )) = 9.

the table tells us

so the change in y-value for function g is (31 -1) = 30.

the change in y-value of f(x) on the interval is less than the change in y-value of g(x) on the same interval, so the average rate of change of f(x) is less than the average rate of change of g(x).