Please help! You pick a card at random, put it back, and then pick another card at random.

What is the probability of picking a number less than 3 and then picking a number greater than 1?

Write your answer as a percentage.

__%

Your answer would be 37.5%

For the first card you picked, the probability of picking a number less than 3 is 2/4 = 1/2, because there are 2 cards that are less than 3 and a total of 4 cards.

When picking the second card, it is still out of 4 because you replaced the first one, so the probability of picking a card greater than 1 is 3/4 because there are 3 cards that are greater than 1 out of a total of 4.

Therefore the total probability would be 1/2 × 3/4 = 3/8. To find this as a percentage we just multiply by 100, and this gives us 37.5%.

I hope this helps!

You have three card : 1, 2, 3 and 4.

You first pick one card randomly, the probability of picking a number less than 3 is:

P = 2/4  

You then pick a second card after putting the first card back, the probability of picking a number greater than 1 is:

P = 3/4

=> The probability of picking a number less than 3 and then picking a number greater than 1:

P = (2/4) x (3/4) = 3/8

Hope this helps!

:)

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step-by-step explanation: