How would you solve dy/dx = 4x - 2, y(-1) = 1 using differential equations?

y=2(x square)-2x-3

Step-by-step explanation:

Let dy with y varibles in a hand

And dx with x variables on the other hand

dy=(4x-2)dx

Then by integration

y=2(square x)-2x+constant

Then substitute by x=-1 and y=1 to find the value of the constant

1=2(1)-2(-1)+ constant

Then constant=-3

Then the equation is

y=2(x square)-2x-3

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.