I REALLY NEED YOUR HELP! Samantha and Jillian were going for a walk. Jillian left 15 seconds ahead of Samantha. • Samantha walked at a speed of 7 feet per second. • Jillian walked at a speed of 6 feet per second. How many seconds had Jillian been walking when the two girls had walked the same distance?
Is the answer 105?

105 seconds

Step-by-step explanation:

To solve this, we can set up an equation.

First, let's find how far ahead Jillian is.

15*6=90

Jillian is 90 feet ahead.

Let's name the time that Samantha walks x.

7x is the distance Samantha walks.

90+6x is the distance Jillian walks.

We want to find how many seconds they have walked when the distance is equal.

So let's form an equation.

7x=90+6x

Subtract 6x from both sides.

x=90

Samantha needs to walk 90 seconds.

Jillian started 15 seconds before that.

90+15=105

Jillian had been walking for 105 seconds when the two girls had walked the same distance.

answer: 21$

step-by-step explanation:

$42 / $14 = 3   (ratio 3: 1)

$7 x 3 = $21