The longest side of an acute isosceles triangle is 8 cm. rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides

the answer is 45 i just did it on oddesy ware

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl

i hope this is what you were looking for.

see attached graph