x^2+{a/a+b + a+b/a}x+1=0 solve for x please solve and i will mark you as the brainliest..its urgent i need to confirm my answer...

x^2 + {a/(a + b) + (a + b)/a}x + 1 = 0

Delta =  {a/(a + b) + (a + b)/a}^2 - 4

         =  {a/(a + b)}^2 + {(a + b)/a}^2 + 2 - 4

         =  {a/(a + b)}^2 + {(a + b)/a}^2  - 2

         =  {a/(a + b) - (a + b)/a}^2

If a is not equal to zero and a is not equal to -b => delta is always larger than 0

=>  Solution 1 =  - [ {a/(a + b) + (a + b)/a} + |{a/(a + b) - (a + b)/a}| ]/2

=>  Solution 2 = - [ {a/(a + b) + (a + b)/a} - |{a/(a + b) - (a + b)/a}| ]/2

Hope this helps!

:)

the infinity sign

step-by-step explanation:

use formula for the circle a=3.14

step-by-step explanation: