Mathematics, 07.06.2020 08:57 jonmorton159
What is 12 radical 2 divided by 2 radical 6 in simplest form
Answers: 1
![\frac{12\sqrt{2}}{2\sqrt{6}}\\\mathrm{Divide\:the\:numbers:}\:\frac{12}{2}=6\\=\frac{6\sqrt{2}}{\sqrt{6}}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}\\\sqrt{6}=6^{\frac{1}{2}}\\=\frac{6\sqrt{2}}{6^{\frac{1}{2}}}\\\mathrm{Apply\:exponent\:rule}:\quad \frac{x^a}{x^b}=x^{a-b}\\\frac{6^1}{6^{\frac{1}{2}}}=6^{1-\frac{1}{2}}\\=\sqrt{2}\cdot \:6^{-\frac{1}{2}+1}\\\mathrm{Subtract\:the\:numbers:}\:1-\frac{1}{2}=\frac{1}{2}\\=6^{\frac{1}{2}}\sqrt{2}](/tpl/images/0679/4936/5e170.png)
![\mathrm{Apply\:radical\:rule}:\quad \:a^{\frac{1}{n}}=\sqrt[n]{a}\\6^{\frac{1}{2}}=\sqrt{6}\\=\sqrt{6}\sqrt{2}\\\mathrm{Factor\:integer\:}6=2\cdot \:3\\=\sqrt{2\cdot \:3}\sqrt{2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{ab}=\sqrt[n]{a}\sqrt[n]{b}\\\sqrt{2\cdot \:3}=\sqrt{2}\sqrt{3}\\=\sqrt{2}\sqrt{3}\sqrt{2}\\\mathrm{Apply\:radical\:rule}:\quad \sqrt{a}\sqrt{a}=a\\\sqrt{2}\sqrt{2}=2\\=2\sqrt{3}](/tpl/images/0679/4936/dc18b.png)
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What is 12 radical 2 divided by 2 radical 6 in simplest form...
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