Which of the following functions has a graph in which the vertex and axis of symmetry are to the left of the vertex and axis of symmetry of the graph of f(x) = (x – 1)2 + 1? Select all that apply. A. g(x) = 2(x − 1)2 − 1
B. g(x) = −(x + 1)2 − 2
C. g(x) = 2(x − 1)2 + 2
D. g(x) = −(x − 2)2 + 1
E. g(x) = −(x + 2)2 + 2
F. g(x) = 2(x + 1)2 + 2

B, E and F.

Step-by-step explanation:

The transformation f(x) > f(x + a) moves f(x) a units to the left.

So when there is an increase in the number added to x in the parentheses the graph moves to the left.

So B is one because  of the (x  - 1)2 ---> (x + 1)2

The others are E and F.

1. perpendicular

2. parallel

3. perpendicular

answer: yes, since the line has a steeper rate of change than the exponential the y-values will be greater and they will only intersect one time.