To cover a distance of 240 km has to increase a speed of 5 per hour to reach in time time. If the time Lost was 40 minutes during traffic find the original speed

The initial speed is approximately 104.3 km

Step-by-step explanation:

Let Distance = 240 km

Time = ?

Speed =

Since

Speed = Distance/Time

Distance = Speed × Time

When arrival is late:

240 = S×T

When arrival is on time:

240 = (S+5)×T2

But 40minutes = 2/3 hours

So,

T2 = T - 2/3

240 = (S+5)×(T - 2/3)

240 = ST - 2S/3 + 5T - 10/3

ST - 2S/3 + 5T = 240 + 10/3

S(T - 2/3) + 5T = 730/3

S(T - 2/3) = 730/3 - 5T

S = (730/3 - 5T)/(T - 2/3)

But 240 = ST

S = 240/T

240/T = (730/3 - 5T)/(T - 2/3)

(T - 2/3)/T = (730/3 - 5T)/240

1 - 2/3T = 730/720 - 5T/240

1 + 73/72 = (2/3 + 5/24)T

145/72 = (7/8)T

T = 145/72 × 8/7

= 1160/504

T = 145/63

S = 240/S

= 240×63/145

= 3024/29

≈ 104.3km

add all the numbers and check the ones place.

the answer is 486. as the ones place is more than 4, the estimation will be the next 10 ie, 490

d

step-by-step explanation: