1. How many solutions does the following equation have? 2x2 – 3x + 5 = 2x2.*- 3x + 5
no solution
- 2x -2% -2X
O
o -5% +5=0
2. Use the quadratic formula to solve the equation. If necessary, round to the nearest
hundredth.
x2 + 3 = -4x+3=- 4x
3- 4x
3. Solve the equation using the Zero-Product Property,
4p(5p+ 10) = 0
20p²+40p=0
-20p^2-20p^2
I just want to know if I got it right?

1. The equation has no real solutions

2. and

3. p = 0 and p = -2

Step-by-step explanation:

1. Eq: x² - 3x + 5

discriminant: b² - 4(a)(c) = (-3)² - 4(1)(5) = 9 - 20 = -19 < 0

Therefore, the equation has no real solutions

2. Eq: x² + 3 = -4x

0 = x² + 4x + 3

3. Eq: 4p(5p+ 10) = 0

Zero-Product Property states that:

4p = 0 or 5p + 10 = 0

The first solution is p = 0. The second is:

5p + 10 = 0

5p = -10

p= -10/5 = -2

solution:

→c= a b , that is product of a and b is possible only when when a is m × n matrix and b is n × p matrix.

that is, number of columns of a= number of rows of b.

so, size of matrix , c= a b is , if a = (m × n)matrix

b= (n × p)matrix

then a b = [ (m × n)matrix] ×[   (n × p)matrix ]

→→c= a b= [m × p ] matrix

→→size of product a b will be equal to = number of rows of a × number of columns of b

irrational, cannot