Alice was flying a kite when a gust of wind caught the kite in a tree. Alice is standing 10 feet from the base of the tree, looking up at her kite at an angle of 25°. If Alice is 5 feet tall, approximately how high is the kite off of the

ground?

A4.66

B 9.66

C 21.45

D 9.23

B. 9.66

Step-by-step explanation:

To find how high the kite is off the ground, we will follow the steps below;

we will use trigonometric ratio to solve the problem. That is;

SOH CAH TOA

sinФ = opposite / hypotenuse

cosФ = opposite / hypotenuse

tanФ = opposite / adjacent

from the diagram below

Ф = 25°

opposite = x

adjacent = 10 feet

The best trig ratio to use is tan

we can now proceed to insert the values into the formula

tanФ = opposite / adjacent

tan 25° =

cross-multiply

x = 10 tan25°

x ≈4.66 feet

height of the kite off of the ground = x + height of Alice

                                                     =4.66 + 5

                                                     =9.66 feet

Therefore, the kite is 9.66 feet high off  of the ground

step-by-step explanation:

30% of $420 is 0.30($420) = $126 and $420 + $126 = $546.

or, 130% of $420 is 1.3($420) = $546.

notice that this is not the $600 original list price with which we started.

why doesn't this work?

the method does not work because 30% of $420 is not the same amount as the 30% of $600. it may seem obvious when stated this way, but it is a very common error made on problems of this type. we cannot just use the same percent and get back to the original amount because we are taking that percent of a different value.

to work problems of this type correctly, it is generally best to write an equation for the situation and then solve.

example: since (100% – 30%)(original price) = (sale price)

70% of the   (original price) is $420.

0.7x   = 420

equation image indicator

x = 600

the original cost was $600.

we may also solve this problem using the two-step method. working the problem in two steps requires us to use more algebra skills. we have to know that x = 1x (identity property of multiplicationtext annotation indicator) and that 1x – 0.3x = 0.7x (subtracting like terms). then we solve the problem as follows:

(original price) – 30%(original price) = sale price

x – 0.3x = 420

0.7x = $420

equation image indicator

x = 600

the original cost was $600.  

note that with both of the above methods we do obtain the correct original amount.

example: after a 5% pay raise, hermione is earning $22,680 per year. what was she earning before the pay raise?

105% of (original salary) = current salary

1.05x = 22,680

equation image indicator

x = 21,600

hermione earned $21,600 per year before the pay raise.

this is an example so maybe you will get how to at least do it!

idc

step-by-step explanation:

idk