In a random sample of 651 computer scientists who subscribed to a web-based daily news update, it was found that the average salary was $46,816 with a population standard deviation of $12,557. Calculate a 91 percent confidence interval for the mean salary of computer scientists. Choose the closest value from your table.

And the confidence interval would be given by: (45981.81; 46650.19)

Step-by-step explanation:

Data given

represent the sample mean

population mean (variable of interest)

represent the population standard deviation

n=651 represent the sample size  

Confidence interval

The confidence interval for the mean is given by the following formula:

  (1)

Since the Confidence is 0.91 or 91%, the significacne is   and , and the critical value is

Now we have everything in order to replace into formula (1):

And the confidence interval would be given by: (45981.81; 46650.19)

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!

"a" determine whether sage found the correct quotient. show your work

step-by-step explanation: