In this diagram, BAC~ EDF. if the area of BAC = 6 in, what is the area of EDF

9in²

Step-by-step explanation:

Area of a triangle = 1/2 × base × height

For ∆BAC, base = 2in and area = 6in²

Substituting to get the height of the triangle

6 = 1/2 × 2 × h

6 = h

Height = 6in

Since ∆BAC ~ ∆EDF, then they will approximately have the same height. Given base of ∆EDF = 3in

Area of ∆EDF = 1/2bh

Area of ∆EDF = 1/2 × 3 × 6

Area of ∆EDF = 9in²

hope it

step-by-step explanation:

x^(1/6) · x^(1/6) · x^(1/6)   ·x^(1/6) = x^(4/6)   since we add the exponents

4/6 can be simplified to 2/3

the simplified form is x^(2/3)

answer

d. 10

explanation

the distance from point y to wx is the height of the triangle.

using pythagoras theorem,

group similar terms to get,

this implies that,

take positive square root of both sides to get,

this implies that,