A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by
h(x)=-(x-11)(x+3)h(x)=−(x−11)(x+3)h , left parenthesis, x, right parenthesis, equals, minus, left parenthesis, x, minus, 11, right parenthesis, left parenthesis, x, plus, 3, right parenthesis
What is the height of the hovercraft at the time of takeoff?
meters

7.9m and 4.3°

step-by-step explanation:

let east be +x and north be +y, x = distance * cos θ, y = distance * sin θ  

for 3.5 south, y = -3.5  

for 8.2, x = 8.2 * cos 30 and y = 8.2 * sin 30  

for 15 west, x = -15  

total x = 8.2 * cos 30 – 15 ≈ -7.9  

total y = -3.5 + 8.2 * sin 30 = 0.6  

magnitude = [(8.2 * cos 30 – 15)^2 + 0.6^2)]^0.5  

the magnitude is approximately 7.9 m  

tan θ = y/x = 0.6/-7.9  

the angle is approximately 4.3˚ north of west

look at the picture i have filled out a table for it. hope this .