Figure ABCD is a rhombus, and m∠BAE = 9x + 2 and m∠BAD = 130°. Solve for x. Rhombus ABCD with diagonals AC and BD and point E as the point of intersection of the diagonals. 3.4 7 14.2 65

x = 14.2 (C)

Step-by-step explanation:

ABCD is a rhombus  and has the following angles given:

m∠BAE = 9x + 2

m∠BAD = 130°

Diagonals of Figure ABCD = AC and BD

The point of intersection of the diagonals = point E

Find attached the diagram obtained from the above information

From the properties if a rhombus, the diagonals bisect the vertex angles of a rhombus. Find attached the diagram for this(1st diagram).

A proof of this property of the diagonals:

a is congruent to b.

a ≅ b

c ≅ d

e ≅ f

g ≅ h

Where ≅ means congruent

From the above, comparing it with the diagram obtained from the information of the question:

9x+2 = 130°

9x = 130-2

9x = 128

x = 128/9

x = 14.2

cant open file sorry!

step-by-step explanation: