What is the equation of the line that passes through (4, -1) and (-2, 3)? 2 x+3y- 5 = 0
-2 x+3y- 5 = 0
2x-3y-5=0

Step-by-step explanation:

(3+1)/(-2-4)= 4/-6= -2/3

y + 1 = -2/3(x - 4)

y + 1 = -2/3x + 8/3

y = -2/3x + 5/3

Multiply both sides by 3

3y = -2x + 5

2x + 3y = 5

2x + 3y - 5 = 0

answer is A

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2