Rectangle A'B'C'D'is the image of rectangle ABCD after it has been translated according to the rule T-43(x, y).
Which points are vertices of the pre-image, rectangle
ABCD? Select four options

(-1,-2)
(7,1)
(-1,7)
(-1,1)
(7,2)

The vertices of the pre-image, rectangle  ABCD are (-1, 1), (7, 1), (7, -2) and (-1, -2).

Step-by-step explanation:

The T-4, 3(x, y) rule of the translation of the pre-image to the image is equal to:

(x, y) = (x - 4, y + 3)

The translation is 4 units to the left and 3 units up .

So  the inverse rule of translation of the image to the pre-image is equal to:

(x', y') = (x' + 4, y' - 3)

Consider the provided image below.

The vertices of the rectangle A'B'C'D' are:

A' = (-5, 4)

B' = (3, 4)

C' = (3, 1)

D' = (-5, 1)

Then the vertices of the rectangle ABCD are:

A = (-5+4, 4-3) = (-1, 1)

B = (3+4, 4-3) = (7, 1)

C = (3+4, 1-3) = (7, -2)

D = (-5+4, 1-3) = (-1, -2)

Thus, the vertices of the pre-image, rectangle  ABCD are (-1, 1), (7, 1), (7, -2) and (-1, -2).

you are saying it as if a fact, not a question, but yes, you would be correct? ; )

step-by-step explanation:

the answer is simply just 6n add the two together as they have an n