What is the equation of the line that is parallel to the line y - 1 = 4(x + 3) and passes through the point (4, 32)? VX
O y=*x+33
O y=-*x+36
O y = 4x - 16
O y = 4x + 16
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y = 4x + 16 (fourth answer choice)

Step-by-step explanation:

From the given equation we can immediately discern that the slope of these lines is 4 (as they are parallel).

Starting with the slope-intercept formula y = mx + b, we get:

32 = 4(4) + b, or 16 = b, or y = 4x + 16

first, you divide the triangle in two, tô form a retangle triangle. after, using pythagoream theorem:

18^2 = 14^2 + (x/2)^2

(x^2/4) + 196 = 324

x^2/4 = 324 - 196

x^2/4 = 128

x^2 = 512

x = √512

x = √2^9

x = 16√2 cm

i hope i you.

x = 2

step-by-step explanation:

if sr parallel to ba then the sides bc and ac are in proportion, that is

= ← substitute values

= ( cross- multiply )

27x = 6(4x + 1)

27x = 24x + 6 ( subtract 24x from both sides )

3x = 6 ( divide both sides by 3 )

x = 2