A box of cereal must weigh more than 629 g and less than 633 g to pass inspectionThe box in which the cereal is packaged weighs 5 g What are the possible weights for the cereal only?

625g ,626g ,627 g

Step-by-step explanation:

Hi, to answer this question we have to write an inequality:

The weight of the cereal (x) plus the weight of the box (5) must be higher than 629 and less than 633.

Mathematically speaking:

629<5+x<633

Solving for x:

629 <5+x

629-5 <x

624<x

5+x<633

x<633-5

x<628

624<x<628

So, the weight of the cereal only must be higher than 624g and less than 628g.

The possible weights are  

625g ,626g ,627 g

Feel free to ask for more if needed or if you did not understand something.  

total = principal × ( 1 + rate ) ^ years

total = 600 * (1.04)^5

total = 729.99

answer is c

step-by-step explanation: