Four horizontal forces of magnitudes 1 N, 2 N, 3N and 4N act at a point in the direction whose bearings are 000, 060, 120 and 720 respectively. a Calculate the magnitude of their resultant. b. A 5th horizontal force of magnitude 3 N now acts at the same points so that the resultant of all five forces has a bearing of 090. Find the bearing of the 5th force

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step-by-step explanation:

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step-by-step explanation:

question 1 is 8, question 2 is 9, question 3 is 24

step-by-step explanation:

now, the numbers they give you at the top are the key. from there, you just have to plug and chug! let's try 1, 2, and 3!

key: a=3, b=5, c=6

1. a+5

remember, a=3, so we plug that in to get 3+5=8

2. 15-c

c=6, so we plug that in to get 15-6=9

3. 4b

b=6, so we plug it in to get 4*6=24

time to try the rest on your own! if you put the answers below in a comment, i'll check them for you!