g You have drawn a simple random sample of 68 college students, asking each student their grade point average (GPA). Each individual draw is normally distributed with a standard deviation of 0.2. You obtain a sample mean grade point average of 2.89. Calculate the upper confidence limit of a 92% confidence interval for the population mean of grade point average. If necessary, round your answer to four decimal places. HINT: For a confidence interval of [a, b] we refer to "a" as the "lower confidence limit" and we refer to "b" as the "upper confidence limit".

The upper confidence limit of a 92% confidence interval for the population mean of grade point average is 2.93.

Step-by-step explanation:

We have that to find our level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of .

So it is z with a pvalue of , so

Now, find the margin of error M as such

In which is the standard deviation of the population and n is the size of the sample.

The upper end of the interval is the sample mean added to M. So it is 2.89 + 0.04 = 2.93.

The upper confidence limit of a 92% confidence interval for the population mean of grade point average is 2.93.

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2

answer is  

minor arc – sw

major arc – stu

semicircle – wst

i got it down chief.