How much water can a rectangular pool hold if it has a length of 30 feet, a width of 25 feet, and is 8 feet deep?

44,886 gallons

Step-by-step explanation:

We need to find the volume

V = l*w*h

V = 30ft*25ft*8ft

V =6000 ft^3

We know that 1 ft^3 = 7.481 gallons

6000 ft^3 * 7.481 gallons/1 ft^3 = 44886 gallons

44,883 gallons

Step-by-step explanation:

The amount of water the pool can hold can be found by calculating the volume of the pool.

We know that the pool is rectangular, and it is a three dimensional shape (3 dimensions: length, width and depth). Therefore, we can use the formula for finding the volume of a rectangular prism:

V=l*w*h

We know the length is 30 feet and the width is 25 feet. The height is also the depth, so the height is 8 feet.

l= 30 feet

w=25 feet

h= 8 feet

Substitute these values into the formula.

V= 30 feet * 25 feet * 8 feet

Multiply the numbers together.

V= (30 feet * 25 feet) * 8 feet

V= 750 feet^2 * 8 feet

V=6000 feet^3

Now, let's find how many gallons the pool can hold.

1 ft^3 is equal to 7.4805 gallons. Therefore, we can multiply 6000 ft^3 and 7.4805

6000 ft^3 * 7.4805 gallons/1 ft^3

6000* 7.4805 gallons

44,883 gallons

The pool can hold 44,883 gallons of water.

from the figure we get,

the x axis shows   the months and,

the y-axis shows the number of satisfied customer.

each line or each cell in upward direction (y-axis) shows 500.

the appropriate scale for the y - axis is: -

a = 2000 customers

b = 4000 customers

c = 6000 customers

d = 8000 customers

e = 10000 customers

f = 12000 customers

g = 14000 customers

-4

step-by-step explanation:

do 6-10=

if u need it to be negative.