What is the equation of a line with a slope of -2 and passes through the point (6,8)

Start with the point-slope formula, shown below in bold.

Our point which in this case is (6, 8) represents (x1, y1) in our formula.

~Substitute

Y - 8 = -2(x - 6)

I will be writing this equation in standard form.

First distribute the -2 through the parentheses.

This gives us y - 8 = -2x + 12.

Next we would move the -8 to the right side of the equation

by adding 8 to both sides to get y = -2x + 20.

Finally we move our x term to the left side of the equation

by adding 2x to both sides and our answer is 2x + y = 20.

step-by-step explanation: h: (- 3, 6)

m: (1, - 2)

o: (7, 6)

r: (- 9, - 2)

midpoint of hm: (- 1, 2)

midpoint of or: (- 1, 2)

therefore, b is the midpoint of both diagonals bisect each other !

to prove the diagonals are perpendicular, show that the product of the slopes = - 1