A long jumper leaves the ground at an angle of above the horizontal, at a speed of 9m/s. The height of the jumper can be modeled by h(x)=-0.049x2+0.366x , where h is the jumper's height in meters and x is the horizontal distance from the point of launch. At what horizontal distance from the point of launch does the maximum height occur? Round to 2 decimal places. Part: 0 / 30 of 3 Parts Complete

+25 = x

step-by-step explanation:

here x is the hypotenuse of a right triangle whose legs are 7 and 24.   by the pythagorean theorem, 7² + 24² must equal x²:

x² = 49 + 576 = 625.   thus, x = +√625 = +25 = x

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stay and stay proud! " - zalgo

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i'm sorry mate, but i am not seeing any figures. i am unable to solve this for you.

actually what is a question i don't understand