The height of a triangle is 4 in. Greater than twice the base. The area of the triangle is no more than 168in^2. Which inequality can be used to find the possible lengths, x, of the base of the triangle

b^2 + 2b <= 168

Step-by-step explanation:

The base is b.

The height, h, is 4 in. greater than twice the base, so the height is 2b + 4.

The area of a triangle is bh/2. We replace h with the expression for height.

A = bh/2 = b(2b + 4)/2 = (2b^2 + 4b)/2 = b^2 + 2b

The area is b^2 + 2b.

The area is no more than 168 in.^2, so it is less than equal to 168 in.^2.

b^2 + 2b <= 168

("<=" means "less than or equal to")

Since you don't show the choices, choose an inequality that is equivalent to the one just above.

your answer would be b

step-by-step explanation:

2/3x + 7 = 29

step-by-step explanation:

two thirds = 2/3

plus a number = x

at least 29 = 29

there for you should get 2/3x + 7 = 29