What is the equation of the line that is parallel to the given line and passes through the point (12, −2)? y = –Six-fifths x + 10 y = –Six-fifths x + 12 y = –Five-sixths x – 10 y = Five-sixths x – 12

y = Five-sixths x – 12

Step-by-step explanation:

In the picture attached, the given line is shown. Its slope is:

m = [6 - (-4)]/[12 - 0] = 5/6

The line that is parallel to the given line has the same slope.

A line with slope m that pass through (x1, y1) satisfies:

y - y1 = m(x - x1)

Replacing with m = 5/6 and point (12, -2):

y - (-2) = 5/6(x - 12)

y + 2 = 5/6x - 10

y = 5/6x - 10 - 2

y = 5/6x - 12

what's that

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: