the average grade in a quiz was 20.0 with a standard deviation of 4.0 the grade follows the normal distribution compete the grade

In the given figure ar(adf) =ar(cda) and ar(cdf) = ar(cdf). show that abdc and cdfe are trapeziums.

32a³b² 8ab² simplify the following expression.

Me answer this question: -2/3p + 1/5 - 1 + 5/6p i think the simplified expression is 1/6p - 4/5 correct me if i'm wrong, and explain it! if i have it right, just tell me. you so