A special type of password consists of 3 different letters of the alphabet, and the two different numbers, where each letter and each number is used only once. How many different possible passwords are there?

There can be 14,040,000 different passwords

Step-by-step explanation:

Number of permutations to order 3 letters and 2 numbers (total 5)

(AAANN, AANNA,AANAN,...)

= 5! / (3! 2!)

= 120 / (6*2)

= 10

For each permutation, the three distinct (English) letters can be arranged in

26!/(26-3)! = 26!/23! = 26*25*24 = 15600 ways

For each permutation, the two distinct digits can be arranged in

10!/(10-2)! = 10!/8! = 10*9 = 90 ways.

So the total number of distinct passwords is the product of all three permutations,

N = 10 * 15600 * 90 = 14,040,000

which expression represents the approximate length of bc?

step-by-step explanation:

d is the correct answer

step-by-step explanation:

x= 8 because 3x = 3 * 8, and 3*8 = 24