What is the coordinate of the vertex of the parabola y-2=1/12(x+10)

Step-by-step explanation:

The equation of a parabola in its vertex form is expressed as y = a(x-h)²+k where (h, k) is the vertex.

Given the equation of a parabola as y-2=1/12(x+10) , we are to write the equation in its vertex form first as shown;

y-2=1/12(x+10)

Adding 2 to both sides of the equation

y=1/12(x+10) +2

y = 1/12x+10/12+2

y = x/12+5/6+2

y = x/12+17/2

comparing the equation above with the quadratic equation y = ax²+bx+c

a = 0, b = 1/12, c = 17/2

The x coordinate of the vertex x = - b/2a

x = - 1/12/2(0)

x = - 1/12(0)

x =-  1/0

x = -

Substitutind x = into the y function, y =- /12+17/2

y = -

The coordinate of the vertex is ()

something over 10 so ? /10

step-by-step explanation: