A school typically sells 500 yearbooks each year for $50. The economics class does a project and discovers that they can sell 100 more yearbooks for every $5 decrease in price. The revenue for yearbook sales is equal to the number of yearbook sold times the price of the yearbook. Let x represent the number of $5 decreases in price. If the expression that represents the revenue is written in the form R(x) = (500 + ax)(50-bx). Find the value of a and b.

a is 100 b is 5

Step-by-step explanation:

a is 100 because if you substitute 100 for a and 1 for x (decrease of 5 dollars) you get 600 yearbooks sold which is a curate according to the economics class prediction

b is 5 because substituting 5 into b and 1 to x gives you 45 dollars per year book. this is accurate because a 5.dollar decrease in price makes the year books 45 dollars instead of 50

step-by-step explanation:

1. practice, practice & more practice

2. review errors

3. master the key concepts

do not try to memorise the processes.

4. understand your doubts.

5. create a distraction free study environment

6. create a mathematical dictionary

7. apply maths to real world problems.

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.