-4x^2+10x-8 how many distinct real number zeros does it have

The equation does not have any real zeroes.

Step-by-step explanation:

The given equation is .

Let us compare it with standard quadratic equation

a = -4

b = 10

c = -8  

The nature of zeroes is determined by Discriminant 'D'.

1. If D = 0, the quadratic equation has two equal real zeroes.

2. If D > 0, the quadratic equation has two unequal real zeroes.

3. If D < 0, the quadratic equation has two non-real or imaginary zeroes.

Formula for D is:

Putting the values of a, b and c to find D:

Here, D is negative so the zeroes of this quadratic equation are imaginary.

Hence, no real zeroes for the given equation .