the density of ethanol is 1.09g/cm^3 the density of propylene is 0.97g/cm^3 80 litres of ethanol are mixed with 148 litres of propylene to make 228 litres of antifreeze work out the density of the antifreeze in g/cm^3

The density of the antifreeze is 1.01 g/cm³

Equations are used to show the relationship between two or more numbers and variables.

Let x represent the density of the antifreeze in g/cm^3.

1 cm³ = 0.001 L

80 L = 80000 cm³; 148 L = 148000 cm³, 228 L = 228000 cm³

Hence:

(1.09 * 80000) + (0.97 * 148000) = x * 228000

228000x = 230760

x = 1.01 g/cm³

The density of the antifreeze is 1.01 g/cm³

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The density of the final mixture is 1.012 g/cm³.

Step-by-step explanation:

To calculate the density of the final mixture we need to know the mass of each solution used is. We will also need to convert the volumes from litres to cm³, to do that we can just multiply 1000.

For the ethanol:

For the propylene:

So the mass in the final mix is the sum of both:

Therefore the density is:

substitute,

circle 1 = 5

circle 2 = 20

circle 3 = 44

in this case no matter how you add, you will always get a perfect square..

hence proved

happy to

pls mark as brainliest

add -60 to 120 which will result in : 2x+3y=180

then subtract 2x: 3y=-2x+180

lastly, divide by 2: y= -2/3x+60

hope this is the answer you're looking for: )