Mathematics, 19.07.2020 14:01 dondre54

Brian is solving the equation x squared minus three-fourths x = 5. What value must be added to both sides of the equation to make the left side a perfect-square trinomial?

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Answer from: oofoofoof1

Term to add is (3/8)^2 = 9/64

Step-by-step explanation:

Here, we want to know the value that must be added to make the equation a perfect square.

x^2 - 3/4x = 5

x^2 -3/4x -(3/8)^2+ (3/8)^2 = 5

x^2 -3/4x + (3/8)^2 = 5 + (3/8)^2

= (x-3/8)^2 = 5 + (3/8)^2

So the term to add is (3/8)^2 = 9/64

Answer from: quianna410

$\dfrac{9}{64}$

Step-by-step explanation:

Given the equation: $x^2-\frac{3}{4}x=5$

To make the left hand side of the equation a perfect trinomial, we follow these steps.

Step 1: Divide the coefficient of x by 2.

Coefficient of x $=-\frac{3}{4}$

$-\frac{3}{4} \div 2 =-\frac{3}{8}$

Step 2: Square your result from step 1

$\implies (-\frac{3}{8})^2 \\=\dfrac{9}{64}$

Therefore, to make the Left-Hand side a perfect-square trinomial, we add 9/64.

Answer from: Quest

Geometric pattern of 2 i’m guessing. not really sure about what you’re asking but i hope this !

Answer from: Quest

8.3 and the 3 is repeating

hope this .

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Brian is solving the equation x squared minus three-fourths x = 5. What value must be added to both...

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