In order to estimate the average time spent on the computer terminals per student at a university, data were collected for a sample of 81 business students over a one week period. Assume the population standard deviation is 1.8 hours. With a 0.95 probability, the margin of error is approximately

The margin of error is approximately 0.39.

Step-by-step explanation:

Formular for the margin of error is

Margin of error = z* (sd/√n)

Where z* is 95% confidence level = 1.96, sd is 1.8 and n is 81

Margin of error = 1.96 (1.8/√81)

= 1.96(1.8/9)

= 1.96*0.2

= 0.392

10.416 meters per second

step-by-step explanation:

distance=1 00 meters

time= 9.6 seconds in decimal form or 9 3/5 as a mixed number

average speed= 100/9.6

=10.416 meters per second or 10 52/125 as a mixed number.

x² + 3x + 7 = 0       [ax² + bx + c]

a = 1

b = 3

c = 7

quadratic formula:

    (+/- is this ±)

plug in the numbers into the variables

your answer is a