Find the Probability that a point chosen randomly inside the rectangle is inside the trapezoid. Enter your answer as a decimal.
10 ft
4 ft
6 ft
4 ft
12 ft
1
2 ft

1/5

Step-by-step explanation:

We need to calculate the area of rectangle and trapezium and the Circumference of the circle.

Area of rectangle :

Length(L) = 10 ; width (W) = 6

Area = L * W = (10 * 6)ft = 60ft^2

Area of trapezium :

Height (h) = 4ft ; length(a) = 2ft ; length(b) = 4ft

Area = 0.5 ( a + b) h

Area = 0.5(2 +4) * 4 = 0.5(6)*4 = 12ft^2

Area of circle :

πr^2 ; r = radius of circle ; r= 2ft

3.142 * 2^2 = 3.142 * 4 = 12.568 ft^2

Probability = required outcome / Total possible outcomes.

P(point chosen inside rectangle is inside trapezium) = Area of trapezium / Area of rectangle

= 12/60

= 1/5

answer: the answer is one

step-by-step explanation:

pemdas, in this situation there is no parenthesis or exponents so you go to multiplication, 1x1=1, then division 1/1= 1 then addition 1+1=2 then subtraction 2-1=1

step-by-step explanation:

duck you