A simple random sample of 49 students at UH indicated that 85% of them are involved in some type club. Find the 99% confidence interval that estimates the true proportion of UH students that are involved in a club

0.85 ± 0.1314

Step-by-step explanation:

P*=0.85

n=49

z for 99% confidence interval = 2.576

The estimates the true proportion of UH students that are involved in a club (99% confidence interval) =

=0.9814, 0.7186

We are 99% confident that the true proportion of UH students that are involved in a club is 0.85 with a margin of error of 0.1314.

the solution is h=10 because you add 9 to each side of the equation.

step-by-step explanation:

if you want to solve percent error follow these steps.

1. subtract the accepted value from the experimental value.

2. take the absolute value of step 1.

3. divide that answer by the accepted value.

4. multiply that answer by 100 and add the % symbol to express the answer as a percentage.

if you want to solve percent of change just do this.

1. work out the difference (increase) between the two numbers you are comparing.

2. divide the increase by the original number and multiply the answer by 100. if your answer is a negative number then this is a percentage decrease.

hope this : )