If a coin is tossed twice find the probability of getting a) 2 heads b) atleast 1 head c) no heads

a) 1/4

b) 3/4

c) 1/4

Step-by-step explanation:

Possible outcomes of two tosses of a coin:

HH

HT

TH

TT

There is a total of 4 possible outcomes.

p(event) = (number of desired outcomes)/(total number of possible outcomes)

a) 2 heads

HH     <  1 desired outcome

HT

TH

TT

p(2 heads) = 1/4

b) at least 1 head

HH   \  

HT      }     < 3 desired outcomes

TH    /

TT

p(at least 1 head) = 3/4

c) no heads

HH

HT

TH

TT    < 1 desired outcome

p(no heads) = 1/4

the answer is ! ?