PLS HELPILL MARK YOU THE BRAINLISt Translate into an algebraic expression and simplify if possible. C It would take Maya x minutes to rake the leaves and Carla y minutes, what portion of the leaves do they rake in one minute if they work together?

(x+y)/xy or  (1/x + 1/y) portion of the leaves

Step-by-step explanation:

Let the total work done to rake the leaves be a for representation.

Thus,

given Maya takes x minutes to rake the leaves

thus,

work done by may in x minutes = a

dividing both side by x

work done by maya in x/x = 1 minutes = a/x

similarly

given Calra takes y minutes to rake the leaves

thus,

work done by may in y minutes = a

dividing both side by y

work done by maya in y/y = 1 minutes = a/y

Total work done by both in 1 minutes = a/x + a/y = a(1/x+1/y) = a(x+y)/xy

Thus, if a is the total work , then they do (x+y)/xy of a work in one minute.

Thus, (x+y)/xy portion of leaves do they rake in one minute if they work together.

1 x=22.52

2: 65/39=604+39x

65x-39x=604

26x=604

x=604/26

×=23.23