ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.

(C) x² - 5x - 14

Step-by-step explanation:

The roots of any quadratic equation will always make the equation equal to 0. So, we can test each equation with the values -2 and 7 to test if both values make the equation 0.

Let's start with A. x² + 5x - 14.

(-2²) + (5 × -2) - 14

4 - 10 - 14 = -20, so we already know that A doesn't work as it doesn't equal 0.

Let's try B. (x+2)² + 7.

(-2+2)² + 7

0² + 7

0+7 = 7, so B doesn't work either.

Let's try C. x² - 5x - 14.

(-2²) - (5×-2) -14

4 + 10 - 14 = 0, ooh we're on to something here! However, for this equation to work, both -2 AND 7 have to work with it. Let's try 7.

(7²) - (5×7) - 14

49 - 35 - 14 = 0, so yes! Both -2 and 7 work for this equation.  Therefore, the roots -2 and 7 work for the quadratic function of x² - 5x - 14, C.

Hope this helped!

i can you with this answer

step-by-step explanation:

30.5*10=350$

you have to multiply the number without the decimal point then add it later but if its tenn u must move the place value of the decimal point 1 to the right.