I made a square frame for my favorite bird picture from four wooden pieces. Each piece is a rectangle with a perimeter of 24 inches. What is the area and perimeter of the picture and frame, together? I don't mind an undetailed explanation c:

The perimeter of the picture frame is 38.4 in.

The area of the picture frame is 92.6 in.².

Step-by-step explanation:

The given information are;

Perimeter of side piece of picture frame = 24 inches

Length of side piece = L

Width of side piece = W

Perimeter of side piece = 2 × (L + W) = 24

∴ L + W = 24/2 = 12 inches

Dimension of picture frame = Square frame with side length s

Number of side piece in picture frame = 4

Given that the length L > the width W, we have

Side length of wooden frame = L

Also, where the side piece are placed side by side, we have;

Side length of wooden frame = 4 × W

Therefore;

4 × W = L

Which gives

L + W = 12 inches

4 × W + W = 12 inches

W×(4 + 1) = 5·W = 12 inches

W = 12/5 = 2.4 inches

L = 4 × W = 4 × 12/5

L = 48/5 = 9.6 inches  Side length of wooden frame, s

The perimeter of the picture frame = 4 × s = 4 × 9.6 = 38.4 in.

The area of the picture frame = s × s = 9.6 × 9.6 = 92.6 in.².

step-by-step explanation:

the answer is c: divide the arc's degree measure by 360°, then multiply by the circumference of the circle.