SOMEONE PLZ HELP ME ON THIS PROBLEM

Step-by-step explanation:

Let's name the function from graph: f

for f:

y-intercept = f(0) = 4

for x → ∞,  f(x)→2

for g:

y-intercept = f(0) = 4(¹/₄)⁰+2 = 4•1+2 = 4+2 = 6 ≠4

f(1) =  4(¹/₄)¹+2 = 4•¹/₄+2 = 1+2 = 3

f(2) =  4(¹/₄)2+2 = 4•¹/₁₆+2 = ¹/₄+2 = 2¹/₄

f(3) =  4(¹/₄)³+2 = 4•¹/₆₄+2 = ¹/₁₆+2 = 2¹/₁₆

f((5) =  4(¹/₄)⁵+2 = 4•¹/₁₈₂₄+2 = ¹/₅₁₂+2 = 2¹/₅₁₂

so for x x → ∞,  f(x)→2

answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

u also answered this so i think u would know but i am here to

put in or use mine