Suppose y varies jointly as x and z. Find y when x=5 and z=6, if y=144 when x=6 and z=10

y=72

Step-by-step explanation:

y varies jointly as x and z

y=k*x*z

Where,

k= constant of proportionality

y=144, x=6, z=10

y=k*x*z

144=k*6*10

144=60k

Divide both sides by 60

144/60=k

2 24/60=k

2 6/15=k

2 2/5=k

k=12/5

Find y when x=5 and z=6

y=k*x*z

y=12/5*5*6

=360/5

=72

y=72

it’s supposed to be -4+45=41

step-by-step explanation: