Shota is a dangerous fellow who likes to go rock climbing in active volcanoes. One time, when he was 303030 meters below the edge of a volcano, he heard some rumbling, so he decided to climb up out of there as quickly as he could. He climbed up at a constant rate. After 4.54.54, point, 5 seconds, he was 7.57.57, point, 5 meters below the edge of the volcano How fast did Shota climb? In total, how long did it take Shota to reach the edge of the volcano?

5m/s;

6 seconds

Step-by-step explanation:

Given the following :

Initial position = 30 m below

He climbed at a constant rate, and was 7.5 m below after 4.5 s.

Distance climbed or covered in 4.5 seconds :

(Initial position - current position)

(30 - 7. 5)m = 22.5 meters

Using the relation:

Speed = distance covered / time taken

Therefore,

Shota's speed = 22.5m / 4.5s = 5m/s

Time taken to reach edge of volcano :

Distance left to cover = 7.5m

Speed = 5m/s

Time required to cover remaining distance :

= distance / speed

= (7.5m ÷ 5m/s) = 1.5s

Total time to reach edge :

(4.5 + 1.5)s = 6 seconds

22 dimes and 9 nickels

step-by-step explanation:

a_n = a_1 + (n - 1)d

the first term is 6.

the common difference d = ?

when you find d, replace n with 7 and d with the common difference to find your answer.