A regular hexagon has vertices at the coordinates listed below. Find the perimeter of the hexagon (-12, -8).(-12, 7), (0, 16), (12,7), (12, -8), (0, -17)
78
99
90
114

Perimeter of the hexagon = 90 Unit

Step-by-step explanation:

Given:

A(-12, -8). B(-12, 7), C(0, 16), D(12,7), E(12, -8), F(0, -17)

Find:

Perimeter of the hexagon

Computation:

Length = √(x1 - x2)² + (y1 - y2)²

AB = √(-12 + 12)² + (-8 - 7)²

AB = 15

BC = √(-12 + 0)² + (7 - 16)²

BC = 15

CD = √(0 - 12)² + (16 - 7)²

CD = 15

DE = √(12 - 12)² + (-7 - 8)²

DE = 15

EF = √(12 - 0)² + (-8 + 17)²

EF = 15

FA = √(0 + 12)² + (-17 + 8)²

FA = 15

Perimeter of the hexagon = AB + BC + CD  + DE + EF + FA

Perimeter of the hexagon = 15 + 15 + 15 + 15 + 15 + 15

Perimeter of the hexagon = 90 Unit

g = (2, 2)

step-by-step explanation:

given the ratio is 1 : 1 then f is the midpoint of eg

let the coordinates of g = (x, y)

using the midpoint formula

(0 + x) = 1 ( multiply both sides by 2 )

0 + x = 2 ⇒ x = 2

similarly

(4 + y) = 3 ( multiply both sides by 2 )

4 + y = 6 ( subtract 4 from both sides )

y = 2

coordinates of g = (2, 2)