PLease Help! I'm Stuck

We can solve this problem in two ways.

1. From the description we conclude that the described sequence is a geometric sequence where the first term a₁ = 2 and common ratio r = 3, so:

Answer D.

2. The easiest way. We know that a₁ = 2, so let's substitute n = 1 for each of the possible answers:

A. 3·2ⁿ = 3·2¹ = 3·2 = 6 - Wrong

B. 2·3ⁿ = 2·3¹ = 2·3 = 6 - Wrong

C. 3·2ⁿ⁻¹ = 3·2¹⁻¹ = 3·2⁰ = 3·1 = 3 - Wrong

D. 2·3ⁿ⁻¹ = 2·3¹⁻¹ = 2·3⁰ = 2·1 = 2 - Correct.

ca = ec

cpctc makes it so that corresponding parts of the triangle you proved to be equal are equal, the other options aren't part of the part of the triangles you proved to be equal.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: